(2x)^1/2-(x-3)^1/2=(5+x)^1/2

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Solution for (2x)^1/2-(x-3)^1/2=(5+x)^1/2 equation: 


x in (-oo:+oo)

((2*x)^1)/2-(((x-3)^1)/2) = ((x+5)^1)/2 // - ((x+5)^1)/2

((2*x)^1)/2-(((x-3)^1)/2)-(((x+5)^1)/2) = 0

(2*x)/2-((x-3)/2)-((x+5)/2) = 0

(-1*(x-3))/2+(-1*(x+5))/2+x = 0

(-1*(x-3))/2+(-1*(x+5))/2+(2*x)/2 = 0

2*x-1*(x-3)-1*(x+5) = 0

2*x-2*x-2 = 0

-2 = 0

-2/2 = 0

-2/2 = 0 // * 2

-2 = 0

x belongs to the empty set

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